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{SECT 0 {EXCHG {PARA 256 "" 0 "" {TEXT 256 35 "Travail 4 Laboratoire 1
2 - Droites " }}}{EXCHG {PARA 256 "" 0 "" {TEXT -1 52 "Par Claude St-H
ilaire, claude.sthilaire@videotron.ca" }}}{EXCHG {PARA 0 "> " 0 "" 
{MPLTEXT 1 0 21 "restart:with(linalg):" }}}{SECT 1 {PARA 3 "" 0 "" 
{TEXT 266 7 "Travail" }}{EXCHG {PARA 0 "" 0 "" {TEXT 257 5 "No 1)" }
{TEXT 258 50 " Soit 3 points A(-5,7,12), B(2,11,-9), C(6,-15,18)" }
{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 97 "a) Trouver 3 points P tel
s que, pour chaque point P, le quadrilat\350re ABCP est un parall\351l
ogramme." }}{PARA 0 "" 0 "" {TEXT -1 75 "b) Calculer la surface de cha
cun des parall\351logrammes. Expliquer la r\351ponse" }}}{SECT 1 
{PARA 3 "" 0 "" {TEXT 267 32 " Espace de travail de l'\351tudiant" }}
{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "
" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}
{EXCHG {PARA 0 "" 0 "" {TEXT 259 6 "No 2) " }{TEXT -1 310 "Soit A(2,5)
, B(-3,55), C(5,31), 3 points. Trouver le point d'intersection des hau
teurs du triangle ABC sachant que les 3 hauteurs d'un triangle se coup
ent en un m\352me point. \nSuggestion : Soit P = [x,y] le point cherch
\351. On doit avoir AP perpendiculaire \340 BC, BP perpendiculaire \+
\340 AC, CP perpendiculaire  \340 AB, " }}}{SECT 1 {PARA 3 "" 0 "" 
{TEXT 268 32 " Espace de travail de l'\351tudiant" }}{EXCHG {PARA 0 ">
 " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "
" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{EXCHG {PARA 0 "" 
0 "" {TEXT 260 6 "No 3) " }{TEXT -1 156 "M\352me probl\350me qu'au no \+
2) mais dans R^3. Soit  A(4,-6,3), B(7,3,-5), C(0,4,-13), trois points
. Trouver le point d'intersection des hauteurs du triangle ABC." }}}
{SECT 1 {PARA 3 "" 0 "" {TEXT 269 32 " Espace de travail de l'\351tudi
ant" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 ">
 " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "
" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT 261 6 "No 4) " }{TEXT -1 64 "Soit A
BC le triangle du No 3) : A(4,-6,3), B(7,3,-5), C(0,4,-13)" }}{PARA 0 
"" 0 "" {TEXT 262 2 "a)" }{TEXT -1 91 " Trouver le point d'intersectio
n de la m\351diatrice au c\364t\351 AC et de la m\351diatrice au c\364
t\351 BC" }}{PARA 0 "" 0 "" {TEXT -1 103 "Rappel : La m\351diatrice \+
\340 un c\364t\351 d'un triangle est la perpendiculaire \351lev\351e s
ur le milieu de ce c\364t\351. " }}{PARA 0 "" 0 "" {TEXT 263 2 "b)" }
{TEXT -1 91 " Trouver le point d'intersection de la m\351diatrice au c
\364t\351 AC et de la m\351diatrice au c\364t\351 AB" }}{PARA 0 "" 0 "
" {TEXT 264 2 "c)" }{TEXT -1 75 " Les 3 m\351diatrices aux c\364t\351s
 du triangle ABC se coupent-elles en un point ?" }}}{SECT 1 {PARA 3 "
" 0 "" {TEXT 270 32 " Espace de travail de l'\351tudiant" }}{EXCHG 
{PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" 
{MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}
{EXCHG {PARA 0 "" 0 "" {TEXT 265 6 "No 5) " }{TEXT -1 115 "D\351montre
r que les trois m\351diatrices d'un triangle ABC dans R^2 se coupent e
n un point, avec les 3 points suivants :" }}}{EXCHG {PARA 0 "> " 0 "" 
{MPLTEXT 1 0 33 "A:=[a1,a2];B:=[b1,b2];C:=[c1,c2];" }}}{SECT 1 {PARA 
3 "" 0 "" {TEXT 271 32 " Espace de travail de l'\351tudiant" }}{EXCHG 
{PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" 
{MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}}}
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